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8x^2+2x-4x=6
We move all terms to the left:
8x^2+2x-4x-(6)=0
We add all the numbers together, and all the variables
8x^2-2x-6=0
a = 8; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·8·(-6)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*8}=\frac{-12}{16} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*8}=\frac{16}{16} =1 $
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